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📐 Chapter 6 · NCERT 2025-26

📐 We Distribute,
Yet Things Multiply

Distributive Property · Algebraic Identities · Multiplication & Division of Expressions

(a+b)²
a²−b²
a(b+c)
3x²y
📐 Introduction & Overview

Have you ever thought about how a shopkeeper quickly calculates the bill for 99 items at ₹15 each? Instead of multiplying 99 × 15 directly, a clever shopkeeper thinks: 99 × 15 = (100 − 1) × 15 = 1500 − 15 = 1485. This is the distributive property in action!

In this chapter, we explore one of the most powerful ideas in algebra: the distributive property of multiplication over addition (and subtraction). This property lets us "distribute" a multiplication across terms that are being added or subtracted, making complex calculations simpler and leading us to powerful algebraic identities.

📚 What You Will Learn
Topic Key Concepts
Distributive Property a(b + c) = ab + ac, distribution over subtraction
Algebraic Expressions Terms, coefficients, like/unlike terms, types of expressions
Multiplication of Expressions Monomial × monomial, monomial × polynomial, polynomial × polynomial
Algebraic Identities (a+b)², (a−b)², (a+b)(a−b), (x+a)(x+b)
Applications of Identities Quick calculation tricks, simplification
Division of Expressions Monomial ÷ monomial, polynomial ÷ monomial
🇮🇳 Indian Mathematical Heritage

India has a rich tradition of algebraic thinking. Long before European mathematicians, Indian scholars developed sophisticated methods for working with algebraic expressions.

📜 Brahmagupta (598–668 CE)

In his work Brahmasphutasiddhanta, Brahmagupta gave rules for multiplying positive and negative numbers, and systematically described algebraic operations — the very foundation of what we study in this chapter.

🌟 Mahavira (c. 850 CE)

The Jain mathematician Mahavira wrote Ganita Sara Sangraha, which contains extensive work on algebraic expressions, fractions, and methods for finding squares and cubes of numbers — effectively using algebraic identities.

💫 Bhaskaracharya (1114–1185 CE)

In Lilavati and Bijaganita, Bhaskara II described the algebraic identities and methods for multiplication and division of expressions that are remarkably similar to what we study today.
💡 Did You Know? The word "algebra" comes from the Arabic al-jabr, but the core ideas of working with unknowns and forming equations have deep roots in Indian mathematics, dating back to the Sulbasutras (800 BCE) and Aryabhata (476 CE).
The Distributive Property
💡 What Is the Distributive Property?

The distributive property states that multiplying a number (or expression) by a sum is the same as multiplying it by each addend separately and then adding the products.

a × (b + c) = a × b + a × c Distributive Property of Multiplication over Addition
a × (b − c) = a × b − a × c Distributive Property of Multiplication over Subtraction

Think of it this way: when you distribute a multiplication, you are sharing it out to every term inside the bracket, just like distributing sweets to every student in a class.

🔢 Numerical Examples

✅ Example: 3 × (4 + 5)

Direct: 3 × 9 = 27
Distributed: 3 × 4 + 3 × 5 = 12 + 15 = 27 ✅

🔵 Example: 7 × (10 − 2)

Direct: 7 × 8 = 56
Distributed: 7 × 10 − 7 × 2 = 70 − 14 = 56 ✅

🟠 Example: 99 × 25

= (100 − 1) × 25
= 100 × 25 − 1 × 25
= 2500 − 25 = 2475

🔸 Example: 102 × 8

= (100 + 2) × 8
= 100 × 8 + 2 × 8
= 800 + 16 = 816
📋 Why Does It Work?

Imagine you have 3 bags. Each bag contains 4 red balls and 5 blue balls. The total number of balls is:

  • Method 1: Each bag has (4 + 5) = 9 balls, so total = 3 × 9 = 27 balls.
  • Method 2: Red balls = 3 × 4 = 12. Blue balls = 3 × 5 = 15. Total = 12 + 15 = 27 balls.

Both methods give the same answer! This is the distributive property at work. It is not just a rule to memorise — it reflects a real-world truth about how quantities combine.

⚡ Distributive Property with Algebra

The distributive property becomes even more powerful when we apply it to algebraic expressions:

🔹 a(x + y)

= ax + ay
Distribute 'a' to both 'x' and 'y'.

🔹 5(2x + 3)

= 5 × 2x + 5 × 3
= 10x + 15

🔹 −3(4a − 7)

= (−3)(4a) − (−3)(7)
= −12a + 21

🔹 2x(3x + 4y − 5)

= 6x² + 8xy − 10x
💡 Memory Aid — "The Postman Rule": Think of the term outside the bracket as a postman who must deliver a letter (multiply) to every house (term) inside the bracket. No house can be skipped!
💡 Important: When distributing a negative sign or negative number, remember that the sign of each product changes: (−)(+) = −, and (−)(−) = +. Be extra careful with signs!
📝 Algebraic Expressions: Terms & Types
📚 What Is an Algebraic Expression?

An algebraic expression is a combination of constants, variables, and arithmetic operations (+, −, ×, ÷). For example, 3x² + 5xy − 7 is an algebraic expression.

📋 Key Vocabulary
Term Meaning Example
Term A product of numbers and variables, separated by + or − signs In 3x² + 5xy − 7: the terms are 3x², 5xy, and −7
Coefficient The numerical factor of a term In 5xy, the coefficient is 5
Constant A term with no variable −7 is a constant term
Like Terms Terms with the same variable parts (same variables raised to the same powers) 3x² and −5x² are like terms
Unlike Terms Terms with different variable parts 3x² and 5xy are unlike terms
📜 Types of Algebraic Expressions

🔹 Monomial

An expression with one term.
Examples: 5x, −3ab, 7, 4x²y

🔹 Binomial

An expression with two terms.
Examples: 3x + 5, a² − b², 2x + 3y

🔹 Trinomial

An expression with three terms.
Examples: x² + 5x + 6, a + b + c

🔹 Polynomial

A general name for expressions with one or more terms where variables have non-negative integer exponents.
Examples: 4x³ − 2x² + x − 7
🛠 Laws of Exponents (Quick Recap)

Before we multiply algebraic expressions, let us recall the key laws of exponents that we will use constantly:

am × an = am+n

When multiplying powers with the same base, add the exponents.
Example: x³ × x² = x5

am ÷ an = am−n

When dividing powers with the same base, subtract the exponents.
Example: x5 ÷ x² = x³

(am)n = amn

When raising a power to a power, multiply the exponents.
Example: (x²)³ = x6

(ab)n = anbn

When raising a product to a power, distribute the exponent.
Example: (2x)³ = 8x³
💡 Sign Rules for Multiplication:
(+) × (+) = +   |   (−) × (−) = +
(+) × (−) = −   |   (−) × (+) = −
Remember: "Same signs → positive, different signs → negative."
Multiplication of Algebraic Expressions
⚡ 1. Monomial × Monomial

To multiply two monomials, multiply the coefficients and then multiply the variable parts using the laws of exponents.

Example 1: Multiply 3x² and 5x³

Step 1: Multiply the coefficients: 3 × 5 = 15
Step 2: Multiply the variables: x² × x³ = x2+3 = x5
Answer: 3x² × 5x³ = 15x5

Example 2: Multiply (−4a²b) and (3ab³)

Step 1: Coefficients: (−4) × 3 = −12
Step 2: Variables: a² × a = a³, and b × b³ = b4
Answer: (−4a²b)(3ab³) = −12a³b4
⚡ 2. Monomial × Polynomial

Use the distributive property! Multiply the monomial by each term of the polynomial separately.

Example 3: Multiply 2x by (3x² + 5x − 4)

Step 1: Distribute 2x to each term:
2x × 3x² + 2x × 5x + 2x × (−4)
Step 2: Calculate each product:
= 6x³ + 10x² − 8x
Answer: 2x(3x² + 5x − 4) = 6x³ + 10x² − 8x
⚡ 3. Polynomial × Polynomial (Binomial × Binomial)

To multiply two binomials, each term of the first binomial must be multiplied by each term of the second binomial. This is sometimes called the FOIL method: First, Outer, Inner, Last.

Example 4: Multiply (x + 3)(x + 5)

Step 1 (First): x × x = x²
Step 2 (Outer): x × 5 = 5x
Step 3 (Inner): 3 × x = 3x
Step 4 (Last): 3 × 5 = 15
Step 5 (Combine): x² + 5x + 3x + 15 = x² + 8x + 15

Example 5: Multiply (2a − 3)(a + 4)

F: 2a × a = 2a²
O: 2a × 4 = 8a
I: (−3) × a = −3a
L: (−3) × 4 = −12
Combine: 2a² + 8a − 3a − 12 = 2a² + 5a − 12
⚡ 4. Polynomial × Polynomial (Trinomial Cases)

Example 6: Multiply (x + 2)(x² + 3x + 1)

Step 1: Distribute x to the trinomial:
x × x² + x × 3x + x × 1 = x³ + 3x² + x
Step 2: Distribute 2 to the trinomial:
2 × x² + 2 × 3x + 2 × 1 = 2x² + 6x + 2
Step 3: Add the results and combine like terms:
x³ + 3x² + x + 2x² + 6x + 2
= x³ + (3x² + 2x²) + (x + 6x) + 2
= x³ + 5x² + 7x + 2
💡 FOIL Mantra: For multiplying two binomials, remember: "First, Outer, Inner, Last" — then combine like terms. For larger polynomials, distribute each term of the first to every term of the second.
💡 Common Mistake: Students sometimes forget to multiply the outer and inner terms. Always check: if you multiply an m-term polynomial by an n-term polynomial, you should initially get m × n products before combining like terms.
💎 Standard Algebraic Identities

An algebraic identity is an equation that is true for all values of the variables. Unlike an equation (which is true only for specific values), an identity holds universally. These identities are derived using the distributive property.

💎 Identity I: (a + b)²
(a + b)² = a² + 2ab + b² Square of a Sum

Derivation:

(a + b)² = (a + b)(a + b)
= a × a + a × b + b × a + b × b
= a² + ab + ab + b²
= a² + 2ab + b²

💡 Geometric Understanding

Imagine a square with side (a + b). Its area = (a + b)². This square can be divided into: one square of area a², one square of area b², and two rectangles each of area ab. So the total area = a² + ab + ab + b² = a² + 2ab + b².
💎 Identity II: (a − b)²
(a − b)² = a² − 2ab + b² Square of a Difference

Derivation:

(a − b)² = (a − b)(a − b)
= a × a + a × (−b) + (−b) × a + (−b) × (−b)
= a² − ab − ab + b²
= a² − 2ab + b²

💡 Key Observation: Notice that (a − b)² = a² − 2ab + b² is not the same as a² − b²! A very common mistake is to write (a − b)² = a² − b². The middle term 2ab must never be forgotten!
💎 Identity III: (a + b)(a − b)
(a + b)(a − b) = a² − b² Difference of Two Squares

Derivation:

(a + b)(a − b) = a × a + a × (−b) + b × a + b × (−b)
= a² − ab + ab − b²
= a² − b²

The middle terms (−ab and +ab) cancel out beautifully, leaving only the difference of the squares.

💎 Identity IV: (x + a)(x + b)
(x + a)(x + b) = x² + (a + b)x + ab Product of Two Binomials with a Common Variable

Derivation:

(x + a)(x + b) = x × x + x × b + a × x + a × b
= x² + bx + ax + ab
= x² + (a + b)x + ab

📊 All Four Identities at a Glance
Identity Expanded Form Key Feature
(a + b)² a² + 2ab + b² Middle term is +2ab
(a − b)² a² − 2ab + b² Middle term is −2ab
(a + b)(a − b) a² − b² No middle term; difference of squares
(x + a)(x + b) x² + (a + b)x + ab Coefficient of x is sum; constant is product
✏️ Verifying an Identity with Numbers

Example 7: Verify (a + b)² = a² + 2ab + b² for a = 3, b = 2

LHS: (3 + 2)² = (5)² = 25
RHS: 3² + 2(3)(2) + 2² = 9 + 12 + 4 = 25
LHS = RHS = 25 ✅ Identity verified!
💡 Memory Aid for Identities I & II:
(a + b)² → "First squared PLUS double product PLUS last squared"
(a − b)² → "First squared MINUS double product PLUS last squared"
The last term b² is always positive (because squaring any number gives a positive result).
💡 Useful Corollaries:
From the identities, we can derive:
(a + b)² − (a − b)² = 4ab
(a + b)² + (a − b)² = 2(a² + b²)
(a + b)² = (a − b)² + 4ab
These are extremely useful in competitive exams!
💡 Applications of Identities for Quick Calculation

One of the most exciting applications of algebraic identities is that they allow us to do mental arithmetic with large numbers quickly.

🔢 Using (a + b)² for Squaring Numbers

Example 8: Find 105² using an identity

Step 1: Write 105 as (100 + 5). So a = 100, b = 5.
Step 2: Apply (a + b)² = a² + 2ab + b²
= 100² + 2(100)(5) + 5²
Step 3: = 10000 + 1000 + 25 = 11025
🔢 Using (a − b)² for Squaring Numbers

Find 97² using an identity

Step 1: Write 97 as (100 − 3). So a = 100, b = 3.
Step 2: Apply (a − b)² = a² − 2ab + b²
= 100² − 2(100)(3) + 3²
Step 3: = 10000 − 600 + 9 = 9409
🔢 Using (a + b)(a − b) for Products

Find 52 × 48 using an identity

Step 1: Notice: 52 = 50 + 2 and 48 = 50 − 2. So a = 50, b = 2.
Step 2: Apply (a + b)(a − b) = a² − b²
= 50² − 2²
Step 3: = 2500 − 4 = 2496
🔢 Using (x + a)(x + b) for Products

Find 103 × 104 using an identity

Step 1: 103 = 100 + 3 and 104 = 100 + 4. So x = 100, a = 3, b = 4.
Step 2: Apply (x + a)(x + b) = x² + (a + b)x + ab
= 100² + (3 + 4)(100) + 3 × 4
Step 3: = 10000 + 700 + 12 = 10712
📊 Quick Calculation Cheat Sheet
Problem Rewrite As Identity Used Answer
53² (50 + 3)² (a + b)² 2500 + 300 + 9 = 2809
98² (100 − 2)² (a − b)² 10000 − 400 + 4 = 9604
71 × 69 (70 + 1)(70 − 1) (a + b)(a − b) 4900 − 1 = 4899
102 × 106 (100 + 2)(100 + 6) (x + a)(x + b) 10000 + 800 + 12 = 10812
999² (1000 − 1)² (a − b)² 1000000 − 2000 + 1 = 998001
💡 Exam Hack: Whenever you see a number close to a "round" number (like 10, 50, 100, 1000), split it using an identity. This saves time and reduces calculation errors. Examiners love testing this skill!
Division of Algebraic Expressions

Division of algebraic expressions is the reverse of multiplication. We use the law of exponents am ÷ an = am−n and cancel common factors.

🔹 1. Monomial ÷ Monomial

Divide the coefficients and subtract the exponents of like variables.

Divide 12x5y³ by 4x²y

Step 1: Divide coefficients: 12 ÷ 4 = 3
Step 2: Divide x-terms: x5 ÷ x² = x5−2 = x³
Step 3: Divide y-terms: y³ ÷ y = y3−1 = y²
Answer: 12x5y³ ÷ 4x²y = 3x³y²
🔹 2. Polynomial ÷ Monomial

Divide each term of the polynomial by the monomial separately.

Divide (8x³ + 12x² − 4x) by 4x

Step 1: Divide each term separately:
8x³ ÷ 4x = 2x²
12x² ÷ 4x = 3x
(−4x) ÷ 4x = −1
Answer: (8x³ + 12x² − 4x) ÷ 4x = 2x² + 3x − 1

Divide (15a³b² − 10a²b³ + 5ab) by 5ab

Step 1: Divide each term:
15a³b² ÷ 5ab = 3a²b
(−10a²b³) ÷ 5ab = −2ab²
5ab ÷ 5ab = 1
Answer: 3a²b − 2ab² + 1
💡 Verification Tip: You can always verify your division by multiplying the quotient by the divisor. If you get back the original dividend, your answer is correct!
For the example above: (2x² + 3x − 1) × 4x = 8x³ + 12x² − 4x ✅
💡 Think of it this way: Dividing a polynomial by a monomial is like distributing the division: (A + B + C) ÷ D = A/D + B/D + C/D. You are "un-distributing" or "reversing" the distributive property!
✏️ NCERT-Style Worked Examples

Problem 1: Expand (2x + 3y)²

Identity: (a + b)² = a² + 2ab + b², where a = 2x, b = 3y
= (2x)² = 4x²
2ab = 2(2x)(3y) = 12xy
= (3y)² = 9y²
Answer: (2x + 3y)² = 4x² + 12xy + 9y²

Problem 2: Expand (5a − 4b)²

Identity: (a − b)² = a² − 2ab + b², where a = 5a, b = 4b
= (5a)² − 2(5a)(4b) + (4b)²
= 25a² − 40ab + 16b²
Answer: 25a² − 40ab + 16b²

Problem 3: Evaluate 95² using an identity

Step 1: 95 = 100 − 5. Using (a − b)² with a = 100, b = 5:
95² = (100)² − 2(100)(5) + (5)²
= 10000 − 1000 + 25 = 9025

Problem 4: Simplify (3x + 7)(3x − 7)

Identity: (a + b)(a − b) = a² − b², where a = 3x, b = 7
= (3x)² − (7)² = 9x² − 49
Answer: 9x² − 49

Problem 5: Find the product (x + 3)(x + 7) using an identity

Identity: (x + a)(x + b) = x² + (a + b)x + ab, where a = 3, b = 7
= x² + (3 + 7)x + (3)(7)
= x² + 10x + 21
Answer: x² + 10x + 21

Problem 6: Using identities, find the value of 104 × 96

Step 1: 104 = 100 + 4 and 96 = 100 − 4. This is (a + b)(a − b) with a = 100, b = 4.
Step 2: = a² − b² = (100)² − (4)² = 10000 − 16
Answer: 104 × 96 = 9984

Problem 7: If a + b = 10 and ab = 21, find a² + b²

Identity: (a + b)² = a² + 2ab + b²
Rearranging: a² + b² = (a + b)² − 2ab
Substituting: = (10)² − 2(21) = 100 − 42 = 58

Problem 8: If a − b = 5 and a² + b² = 41, find ab

Identity: (a − b)² = a² − 2ab + b²
Substituting: (5)² = 41 − 2ab
25 = 41 − 2ab
2ab = 41 − 25 = 16
ab = 8
📊 Chapter Summary
📋 All Key Identities at a Glance
(a + b)² = a² + 2ab + b² Identity I — Square of a Sum
(a − b)² = a² − 2ab + b² Identity II — Square of a Difference
(a + b)(a − b) = a² − b² Identity III — Difference of Two Squares
(x + a)(x + b) = x² + (a + b)x + ab Identity IV — Product of Binomials
📚 Key Concepts Recap
Concept Key Point
Distributive Property a(b + c) = ab + ac; the basis for all multiplication of expressions
Monomial × Monomial Multiply coefficients; add exponents of like variables
Monomial × Polynomial Distribute the monomial to each term of the polynomial
Polynomial × Polynomial Multiply each term of one by every term of the other; combine like terms
Division by Monomial Divide each term separately; subtract exponents of like variables
Identity An equation true for ALL values of the variables, not just specific ones
⚠️ Common Mistakes to Avoid

❌ (a + b)² ≠ a² + b²

The middle term 2ab is essential. Never forget it!
Correct: (a + b)² = a² + 2ab + b²

❌ (a − b)² ≠ a² − b²

The expansion of (a − b)² is a² − 2ab + b², not a² − b².

❌ x² × x³ ≠ x6

When multiplying, add the exponents: x² × x³ = x5.
You multiply exponents only when raising a power to a power: (x²)³ = x6.

❌ Sign errors in distribution

−3(2x − 5) = −6x + 15, NOT −6x − 15.
Remember: negative × negative = positive!
💡 Exam Day Checklist:
✅ Write the identity/formula before substituting values
✅ Be careful with signs, especially when distributing negatives
✅ When using identities for quick calculation, identify 'a' and 'b' clearly
✅ Verify your expansion by substituting small numbers
✅ Combine all like terms in your final answer
✅ For division, verify by multiplying quotient by divisor
🧠 Multiple Choice Questions (10 MCQs)

Click on an option to see if your answer is correct. The correct option will turn green.

  • Q1. The expansion of (a + b)² is:
    • a) a² + b²
    • b) a² + 2ab + b²
    • c) a² − 2ab + b²
    • d) a² + ab + b²
    ✅ Answer: (b) a² + 2ab + b² — This is Identity I. The middle term 2ab must not be forgotten.
  • Q2. What is the product (x + 5)(x − 5)?
    • a) x² + 25
    • b) x² + 10x − 25
    • c) x² − 25
    • d) x² − 10x + 25
    ✅ Answer: (c) x² − 25 — Using (a + b)(a − b) = a² − b² with a = x, b = 5.
  • Q3. 3x² × 4x³ equals:
    • a) 12x6
    • b) 12x5
    • c) 7x5
    • d) 12x5y
    ✅ Answer: (b) 12x5 — Multiply coefficients (3 × 4 = 12) and add exponents (2 + 3 = 5).
  • Q4. Using an identity, 99² equals:
    • a) 9801
    • b) 9901
    • c) 9801
    • d) 9800
    ✅ Answer: (a)/(c) 9801 — 99² = (100 − 1)² = 10000 − 200 + 1 = 9801.
  • Q5. The coefficient of x in the expression 7x² + 3x − 5 is:
    • a) 7
    • b) 3
    • c) −5
    • d) 1
    ✅ Answer: (b) 3 — The coefficient of x is the numerical factor of the term containing x (not x²), which is 3.
  • Q6. (a − b)² is equal to:
    • a) a² − b²
    • b) a² + 2ab − b²
    • c) a² − 2ab + b²
    • d) a² − 2ab − b²
    ✅ Answer: (c) a² − 2ab + b² — The last term b² is always positive because (−b)² = b².
  • Q7. An expression with three terms is called a:
    • a) Monomial
    • b) Binomial
    • c) Trinomial
    • d) Polynomial
    ✅ Answer: (c) Trinomial — Mono = 1, Bi = 2, Tri = 3 terms. (Note: "Polynomial" is also technically correct as a general term, but "Trinomial" is the specific name.)
  • Q8. (x + 3)(x + 5) = x² + ?x + 15. The missing coefficient is:
    • a) 3
    • b) 5
    • c) 8
    • d) 15
    ✅ Answer: (c) 8 — Using (x + a)(x + b) = x² + (a + b)x + ab. Here a + b = 3 + 5 = 8.
  • Q9. 12x³y² ÷ 3xy equals:
    • a) 4x³y²
    • b) 4x²y
    • c) 4xy
    • d) 9x²y
    ✅ Answer: (b) 4x²y — 12 ÷ 3 = 4, x³ ÷ x = x², y² ÷ y = y.
  • Q10. If a + b = 7 and ab = 12, then a² + b² equals:
    • a) 49
    • b) 25
    • c) 37
    • d) 19
    ✅ Answer: (b) 25 — a² + b² = (a + b)² − 2ab = 49 − 24 = 25.
✍️ Short Answer Questions (NCERT Q&A)
  • Q1. State the distributive property of multiplication over addition.
    The distributive property states that for any three numbers a, b, and c: a × (b + c) = a × b + a × c. It allows us to "distribute" the multiplication over the addition.
  • Q2. What is the difference between an identity and an equation?
    An identity is a statement that is true for all values of the variables. For example, (a + b)² = a² + 2ab + b² is true for any a and b. An equation is true only for specific values (called solutions). For example, 2x + 3 = 7 is true only when x = 2.
  • Q3. Expand: (3p + 4q)²
    Using (a + b)² = a² + 2ab + b² with a = 3p, b = 4q:
    = (3p)² + 2(3p)(4q) + (4q)²
    = 9p² + 24pq + 16q²
  • Q4. Find the product: (2x + 5)(2x − 5)
    Using (a + b)(a − b) = a² − b² with a = 2x, b = 5:
    = (2x)² − (5)² = 4x² − 25
  • Q5. Multiply: 5x²y × (−3xy²)
    Coefficients: 5 × (−3) = −15
    Variables: x² × x = x³, y × y² = y³
    Answer: −15x³y³
  • Q6. Evaluate 103² using a suitable identity.
    103 = 100 + 3. Using (a + b)² = a² + 2ab + b²:
    = (100)² + 2(100)(3) + (3)²
    = 10000 + 600 + 9 = 10609
  • Q7. Simplify: (x + 4)(x + 6) using the identity (x + a)(x + b).
    Using (x + a)(x + b) = x² + (a + b)x + ab with a = 4, b = 6:
    = x² + (4 + 6)x + (4)(6)
    = x² + 10x + 24
  • Q8. Divide: (9a³b² + 6a²b) by 3ab
    Divide each term:
    9a³b² ÷ 3ab = 3a²b
    6a²b ÷ 3ab = 2a
    Answer: 3a²b + 2a
  • Q9. Find the value of 51 × 49 using an identity.
    51 = 50 + 1 and 49 = 50 − 1.
    Using (a + b)(a − b) = a² − b²:
    = 50² − 1² = 2500 − 1 = 2499
  • Q10. What are like terms? Give an example.
    Like terms are terms that have exactly the same variable parts — the same variables raised to the same powers. Only the coefficients may differ.
    Example: 3x²y and −7x²y are like terms because both have x²y. However, 3x²y and 3xy² are unlike terms.
📖 Long Answer Questions (NCERT Q&A)
Q1. Derive the identity (a + b)² = a² + 2ab + b² using the distributive property. Also verify it for a = 4 and b = 3.
Derivation:
(a + b)² = (a + b)(a + b)

Using the distributive property, multiply each term of the first bracket by each term of the second:
= a(a + b) + b(a + b)
= a² + ab + ba + b²
= a² + ab + ab + b²    (since ba = ab)
= a² + 2ab + b²

Verification for a = 4, b = 3:
LHS = (4 + 3)² = 7² = 49
RHS = 4² + 2(4)(3) + 3² = 16 + 24 + 9 = 49
LHS = RHS = 49 ✅ Hence verified.
Q2. Explain all four standard algebraic identities with examples. Show how each can be used for quick numerical calculations.
Identity I: (a + b)² = a² + 2ab + b²
Example: (x + 3)² = x² + 6x + 9
Calculation: 52² = (50 + 2)² = 2500 + 200 + 4 = 2704

Identity II: (a − b)² = a² − 2ab + b²
Example: (y − 4)² = y² − 8y + 16
Calculation: 48² = (50 − 2)² = 2500 − 200 + 4 = 2304

Identity III: (a + b)(a − b) = a² − b²
Example: (m + 7)(m − 7) = m² − 49
Calculation: 63 × 57 = (60 + 3)(60 − 3) = 3600 − 9 = 3591

Identity IV: (x + a)(x + b) = x² + (a + b)x + ab
Example: (x + 2)(x + 8) = x² + 10x + 16
Calculation: 101 × 103 = (100 + 1)(100 + 3) = 10000 + 400 + 3 = 10403

These identities transform lengthy multiplications into simple arithmetic with round numbers, saving time in exams and real-life calculations.
Q3. Multiply (2x + 3)(3x² − 2x + 5) and verify your answer by substituting x = 1.
Multiplication:
(2x + 3)(3x² − 2x + 5)

Distribute 2x to the trinomial:
2x × 3x² = 6x³
2x × (−2x) = −4x²
2x × 5 = 10x

Distribute 3 to the trinomial:
3 × 3x² = 9x²
3 × (−2x) = −6x
3 × 5 = 15

Adding all terms:
6x³ − 4x² + 10x + 9x² − 6x + 15
= 6x³ + (−4x² + 9x²) + (10x − 6x) + 15
= 6x³ + 5x² + 4x + 15

Verification at x = 1:
LHS: (2(1) + 3)(3(1)² − 2(1) + 5) = (5)(3 − 2 + 5) = 5 × 6 = 30
RHS: 6(1)³ + 5(1)² + 4(1) + 15 = 6 + 5 + 4 + 15 = 30
LHS = RHS ✅ Verified!
Q4. If x + 1/x = 6, find the values of: (i) x² + 1/x² (ii) x² − 1/x² given x − 1/x = 4.
(i) Finding x² + 1/x²:
We know (x + 1/x)² = x² + 2(x)(1/x) + 1/x² = x² + 2 + 1/x²

So x² + 1/x² = (x + 1/x)² − 2
= (6)² − 2 = 36 − 2 = 34

(ii) Finding x² − 1/x²:
Using the identity a² − b² = (a + b)(a − b) where a = x, b = 1/x:
x² − 1/x² = (x + 1/x)(x − 1/x)
= (6)(4) = 24
Q5. Explain the process of dividing a polynomial by a monomial with a detailed example. Also explain how division is the reverse of multiplication.
Process: To divide a polynomial by a monomial, we divide each term of the polynomial by the monomial separately, using the rules: divide coefficients and subtract exponents of like variables.

Example: Divide (18x4y³ − 12x³y² + 6x²y) by 6x²y

Term 1: 18x4y³ ÷ 6x²y = (18/6) × x4−2 × y3−1 = 3x²y²
Term 2: (−12x³y²) ÷ 6x²y = (−12/6) × x3−2 × y2−1 = −2xy
Term 3: 6x²y ÷ 6x²y = 1

Answer: 3x²y² − 2xy + 1

Verification (Division is the reverse of multiplication):
(3x²y² − 2xy + 1) × 6x²y
= 3x²y² × 6x²y − 2xy × 6x²y + 1 × 6x²y
= 18x4y³ − 12x³y² + 6x²y ✅

This confirms that division is indeed the reverse of multiplication. When we divide polynomial P by monomial M to get quotient Q, then Q × M = P.
🌟 Fun Facts & Did You Know?

🔢 The Power of Distribution

The distributive property is used billions of times every second inside your phone's processor. Every digital calculation — from opening an app to playing a video — relies on circuits that "distribute" operations across binary numbers.

🇮🇳 India's Algebraic Heritage

Brahmagupta (628 CE) wrote rules for multiplying positive and negative numbers in Brahmasphutasiddhanta. He stated that "the product of two debts (negative numbers) is a fortune (positive)" — the same sign rule we use today!

📈 Identities in Architecture

Ancient Indian temple architects used algebraic identities to calculate areas of complex floor plans. The identity (a + b)² = a² + 2ab + b² helped them divide large squares into smaller manageable pieces for construction.

🎨 Art of Quick Squaring

Vedic Mathematics uses the identity (a + b)(a − b) = a² − b² to square numbers mentally. To find 47²: note 47 × 47 = (47 + 3)(47 − 3) + 3² = 50 × 44 + 9 = 2200 + 9 = 2209!

💻 FOIL in Computer Science

Polynomial multiplication (the FOIL method extended) is the basis for many algorithms in computer science, including Fast Fourier Transform (FFT), which is used in audio processing, image compression, and even 4G/5G mobile signals.

🚀 Algebra in Space

ISRO scientists use algebraic expressions and identities to simplify complex trajectory equations. When computing orbital mechanics for satellites, quick algebraic simplification saves precious computation time.

💫 The Word "Algebra"

The word comes from the Arabic title Kitab al-Jabr by al-Khwarizmi (820 CE). But al-Khwarizmi himself acknowledged that his work built upon Indian mathematical traditions, particularly the works of Brahmagupta.

🧮 The Largest Known Prime

The largest known prime number (as of 2024) has over 41 million digits! Finding such numbers requires massive polynomial arithmetic — essentially the multiplication and factoring of algebraic expressions on a cosmic scale.
💡 Think About It: Every time you simplify an expression, use an identity, or multiply polynomials, you are using the same mathematical tools that engineers use to build bridges, scientists use to model the universe, and programmers use to create the apps on your phone. Algebra is the language of problem-solving!
🃏 Quick Revision Flashcards

Use these flashcards for last-minute revision before your exam. Read the question, try to answer mentally, then check!

Q: What is (a + b)²?

A: a² + 2ab + b²

Q: What is (a − b)²?

A: a² − 2ab + b²

Q: What is (a + b)(a − b)?

A: a² − b²

Q: (x + a)(x + b) = ?

A: x² + (a+b)x + ab

Q: x³ × x4 = ?

A: x7 (add the exponents)

Q: What is a monomial?

A: An expression with one term. Example: 5x²y

Q: Find 101² quickly.

A: (100+1)² = 10000 + 200 + 1 = 10201

Q: Is (a+b)² = a² + b²?

A: NO! The middle term 2ab is missing.

Q: 6x² ÷ 2x = ?

A: 3x

Q: Like terms of 5xy: 3xy or 3x²?

A: 3xy is like; 3x² is unlike.

Q: Coefficient of x in 7x² − 3x + 2?

A: −3

Q: 52 × 48 using identity?

A: (50+2)(50−2) = 2500 − 4 = 2496
💡 Final Revision Mantra:
Distribute → Multiply every term inside the bracket by the term outside.
FOIL → First, Outer, Inner, Last for binomial × binomial.
Identities → (a+b)², (a−b)², (a+b)(a−b), (x+a)(x+b).
Signs → Same signs give +, different signs give −.
Exponents → Add when multiplying, subtract when dividing.
Verify → Substitute small numbers to check your answer.

You've got this! Go ace that exam! 💪

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